176  Modern  Commercial  Wiring  Copyright  Goodheart-Willcox  Co.,  Inc.  SAMPLE  PROBLEM  12-8  Pro  r  ob  lem:  Determine  (a)  the  re  ec  eptacle  load  for  a  an  80′  ×  120′  hardware  store  a  an  d  (b)  the  number  of  15-amp  circuits  needed  t  to  supply  the  load.  The  number  of  receptacles  s  is  unknown.  Solution:  (a)  The  numb  m  be  r  of  receptacles  is  unknown,  so  a  receptacle  ac  load  of  1  VA/ft2  can  be  calculated:  Area  =  80′  ×  120′  0  ′  =  9600  ft2  t  2  Receptacle  load  oa  =  1  VA/ft2  ×  9600  ft2  =  9600  VA  (b)  To  determ  mi  ne  the  number  of  circuits  required,  qu  fi  rst  calculate  te  the  allowable  load  for  a  single  e  circuit:  fi  Max  loa  o  ad  =  120  V  ×  15  A  =  1800  VA  Divide  e  the  total  receptacle  load  by  b  y  the  maxi-  mum  m  load  per  circuit  to  determine  in  the  mini-  mum  u  number  of  circuits:  Circuits  =  96_____VA00__  1800  V  =  5.33  This  is  the  minimum  numbe  er  ,  so  round  up  to  six  circuits.  SAMPLE  PROBLEM  12-9  Problem:  The  hardwa  ar  e  store  introduced  in  Sample  Problem  12-5  -  will  have  one  duplex  receptacle  for  every  12′  1  of  wall  around  the  stor-  age  area  and  showro  oo  m.  A  total  of  twelve  floor  r  fl  receptacles  will  be  used.  Determine  the  recep  p-  tacle  load,  including  n  show-window  receptacles  le  for  20′  and  25′  show  ho  windows.  S  Sh  owroom  Storage  area  (Continued)  Solution:  Receptacles  will  be  e  placed  along  six  80′-long  walls  and  two  40′-long  40  walls.  Deter-  mine  the  number  of  receptacles  ec  needed  for  each  80′-long  wall:  Receptacles  per  e  r  80′  wall  =  _80′_  12′  =  6.67  Seven  receptacles  ce  are  needed  for  each  80′  wall.  Next,  determine  de  the  number  of  receptacles  s  neede  d  ed  for  each  40′  wall:  Receptacles  per  40′  wall  =  _40′_  12′  =  3.33  Four  receptacles  are  needed  for  r  each  40′  wall.  The  total  number  of  wall  receptacles  ep  can  now  be  calculated:  Wall  receptacles  =  (6  6  ×  ×  7)  +  (2  ×  4)  =  =  42  +  8  =  50  One  receptacle  c  le  is  needed  for  every  12′  of  show  window  o  length,  so  the  20′  show  window  requires  tw  t  wo  receptacles  and  the  25′  show  win-  dow  req  e  qu  ires  3  receptacles.  Therefore,  the  show  windows  d  require  a  total  of  fi  ve  receptacles  e  s.  fi  The  Th  total  number  of  receptacles  can  be  found  ou  b  by  adding  together  the  wall  receptacles,  s,  floor  fl  receptacles,  and  show-window  receptac  a  cl  es:  Total  receptacles  =  50  +  12  +  5  =  67  receptacles  p  ta  The  total  receptacle  load  a  d  can  then  be  determined:  Receptacle  load  =  6  67  ×  180  VA  =  12,060  VA  The  total  recepta  ac  le  load  is  12,060  VA.  For  feeder  sizing,  the  first  r  st  10,000  VA  must  be  counted  at  fi  100%,  but  o  on  ly  50%  of  the  additional  load  needs  to  be  con  ns  idered.  Determine  50%  of  2060  VA:  206  0  60  VA  ×  0.50  =  1030  VA  Feeder  load  =  10,000  VA  +  1030  VA  =  11,030  VA  The  receptacle  load  on  the  feeder  is  11,030  VA.  
